If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2-19x+3x=0
We add all the numbers together, and all the variables
9x^2-16x=0
a = 9; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·9·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*9}=\frac{32}{18} =1+7/9 $
| 1=(15x-5) | | 8x-6=5-6x | | 3x+4=−5 | | X=425+y | | 6g=126 | | 7x-15=7x-21 | | x/x+3=8/x+6 | | Y=32(1/2)x+1 | | P=-0.5(x-2)(x-12) | | -2(4y-3)-8y+6=4(y-2-2) | | -2(4y-3)-8y+6=4(y-2 | | 7x-15=7(x-3) | | 10(z+5)=70 | | 2x+4x-6=0 | | (x+17)/2=5 | | x2+2=x4+3 | | 13-2d=7 | | -2(x+4)=-4(x+5) | | 2^x3=256 | | 6y-21=51 | | 3(x-2)+x=x-3 | | 4s+16=36 | | -1=9-2g | | -28+m=-47 | | 44h+45=179 | | -6x-3=-4+1 | | 3000=900+85x | | 8f+27=2f+111 | | -38+y=26 | | (11+2i)–(3–10i)=11+2i–3–10i=(11–3)+(2i–10i)=8–8i | | -6(n-96)=-18 | | 7+3k=13 |